-5y^2+5y=0

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Solution for -5y^2+5y=0 equation: 



-5y^2+5y=0

a = -5; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-5)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-5}=\frac{-10}{-10}
=1
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-5}=\frac{0}{-10}
=0
$

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